00:01
Hi, the new value of speed will be n nu is equal to 1 minus 75 divided by 100 into 1 ,140 rpm.
00:16
So we will get 285 rpm.
00:21
Then first back emf, eb is equal to vt that is 455 minus i.
00:30
That is 9 into r a that is 0 .2 it will be equal to 453 .2 volt then the new value of back emf that is eb new will be equal to n new divided by n into eb so we can substitute the values that is 285 divided by 1 ,140 into 453 .2.
01:09
By solving this, we will get 113 .3 volt.
01:15
The value of our mature voltage, that is vt dash, is equal to e v, new, that is 113 .3, plus ia, that is 9 into ra is 0 .2, that will be equal to 115 .1 volts.
01:37
Then the armature voltage under holding condition of the motor will be, that is vt hold, is equal to 0 plus ia, that is 9 into ra is 0 .2, will be equal to 1 .8 volts...