Question

A 460-V rms 60-Hz load uses 12 kW at a lagging power factor of 0.75. What capacitance should be placed in parallel with the load to correct the power factor to 0.9 lagging?

Name: a 460 v rms 60 hz load uses 12 kw at a lagging power factor of 075 what capacitance should be placed in parallel with the load to correct the power factor to 09 lagging 92782
Uploaded: 2024-05-07T10:22:41-08:00
Duration: 2 min 3 s
Channel: Adi S
Description: a 460 v rms 60 hz load uses 12 kw at a lagging power factor of 075 what capacitance should be placed in parallel with the load to correct the power factor to 09 lagging 92782

          A 460-V rms 60-Hz load uses 12 kW at a lagging power factor of 0.75. What capacitance should be placed in parallel with the load to correct the power factor to 0.9 lagging?

Added by Amanda F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

05/07/2024

Step 1

The apparent power in VA (volt-amperes) can be calculated using the formula: \[ S = \frac{P}{\text{Power Factor}} \] where \( P \) is the real power in watts. Given that \( P = 12,000 \) watts (or 12 kW) and the initial power factor is 0.75, we can calculate the Show more…

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A 460-V rms 60-Hz load uses 12 kW at a lagging power factor of 0.75. What capacitance should be placed in parallel with the load to correct the power factor to 0.9 lagging?