00:03
Let x be the horizontal distance, which is the distance from the bottom of the ladder to the wall, y being the vertical distance, which is the height of the ladder on the wall and z being the hypotenuse, which is the length of the ladder.
00:33
The value of z is said to be 5 and dx by dt is equal to 8 meter per second square, which is the rate at which bottom of the ladder is being pushed horizontally.
00:46
So z square is equal to x square wherein we add y square.
00:51
Differentiating both the sides with respect to time t, we get 2z multiplied by dz divided by dt, which is equal to 2x multiplied by dx divided by dt, to which we add 2y multiplied by dy by dt.
01:13
So when the value of x is said to be 0 .4 meters, we are given that z is equal to 5, x is equal to 0 .4 and dx by dt is equal to 8 meter per second square.
01:37
So finding the y as z square is equal to x square wherein we add y square, 5 square is equal to 0 .4 square wherein we add y square.
01:53
The value of, so we get 25 is equal to 0 .6 plus y square.
01:59
Y square then is 24 .84.
02:04
The value of y is approximately 4 .984 meters...