A 50 kW, 120 volts, Short Shunt DC Generator has a rotational loss amounting to 580 watts. The shunt field resistance is 62.5 ohms, the series field resistance is 0.002 ohms, and the armature resistance is 0.12 ohms. What is the efficiency?
Added by William C.
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The output power (\(P_{out}\)) is given as 50 kW and the terminal voltage (\(V\)) is 120 volts. \[ I_L = \frac{P_{out}}{V} = \frac{50000 \text{ W}}{120 \text{ V}} = 416.67 \text{ A} \] Show more…
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