A 60 Hz and 250 km long transmission line has an impedance of 33 + j104 Ω and a total shunt admittance of 10^-3 mho. The receiving end load is 50 MW at 208 kV with a power factor of 0.8 lagging. Find the sending end voltage, current, power, and power factor using the Short line transmission line method and Medium line (π and T) transmission line method.
Answer:
Vs = 235.33<4.620 kV,
Is = 0.173<-36.870 kA,
Ps = 52.88 MW
Vs = 224<3.720 kV,
Is = 0.135<10.250 kA,
Ps = 52.4 MW: π
Vs = kV,
Is = kA,
Ps = MW: T