Three phase transmission line receiving end voltage is rated...

The three-phase transmission line receiving end voltage is rated at 21 kV. A load of 1250 kW is connected at the receiving end of the transmission line, which is 60 km long. The parameters of the transmission line are given by r = 0.09 Î©/km and x = 0.7 Î©/km. If the machine is working at a power factor of 0.85 lagging, determine: a) The series reactance of the transmission line b) Sending end line voltage c) Percentage Voltage regulation d) Percentage Efficiency

Transcript

00:01 A three -phase transmission line receiving the end voltage at 22 kilowolts amp a load of 1 250 kilo watt is connected at the receiving end of the transmission line which is 70 kilometer long the parameters of the transmission line are equal 0 .09 q per kilometer and x is 0 .7 q per kilometer if the machine is working at the power factor 0 .65 lag then determine the series resistance of the transmission line and sending end line voltage and line voltage c the percentage voltage the percentage voltage regulation d the percentage efficiency of series resistance equals rl equals 0 .09 multiply 70 this will be 6 .3 oms then series reactance is equals to xl substituting the value 0 .7 oom per kilometer multiplied by 70 kilometers.

02:02 This is 49 oom and the total impedance z equal 6 .3 plus j 49 om.

02:21 We know that for a three phase power is equal to root 3 vr ir coss 5 i r is equals to p by root 3 vr x substituting the value 1 -250 into 10 raised with power 3 divided by root 3 into 22 10 raise with power 3 multiply 0 .65 is the power factor on solving this current 50 .467 angle minus 49 .458 then vsp is equal to vrp where s represents sending and r is the receiving plus z into ir then we have vsp is equal to 22 kilowalt by root 3 plus 6 .3 plus j 49 multiplied 50 .467 angle minus 49 .458.

03:33 From here on solving, vsp is equals to 14 .85 kilowalt angle 5 .276 degrees.

03:48 Then vsl line voltage at the sending end is root 3 times vsp.

03:56 This will be 25 .72 multiply 5 .276 and so the sideline voltage is 25 .72 angle 5 .27 to find the percentage voltage regulation the percentage regulation can be defined by vs minus vr their magnitude by magnitude of vr into 100.

04:35 Plug the values 25 .72 minus 22 by 22 by 22 into 100...

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