00:01
Hi, so we are solving for the final temperature of water.
00:06
So we will use this formula for heat due to temperature change, mass, specific heat, change in temperature.
00:11
Let's rearrange this to solve for the change in temperature.
00:14
First we'll have heat divided by mass and then the specific heat capacity.
00:18
So the amount of heat absorbed by water is 165 j.
00:23
The mass of the water sample is 6 .50 g.
00:28
Specific heat capacity of liquid water is 4 .18 j per g, degree celsius.
00:33
Let's cancel some units, grams, j.
00:36
Then we have here the remaining unit which is degree celsius.
00:41
And then this will give us 6 .0729 degree celsius...