00:01
Hello, here the grade has a mass of 45 kilograms and that's pushed from rest by friction by a horizontal force, which is 120 newtons on a horizontal plane from point b to point b, which are separated by the distance of 80 meters.
00:22
The coefficient of friction is 0 .2 and first we have to calculate the work done by the force f.
00:30
This work done by force f equals to f times t, which is 120 newtons times 80 meters.
00:41
That is 9 ,600 jules.
00:46
Now let's answer question b.
00:48
Here we have to calculate much work is dissipated by the friction, so it means that we have to calculate absolute value of the friction force.
00:59
That equals to the friction force.
01:02
Times d which is mu k m g times d so that is 0 .2 times 45 kilograms times 9 .8 meters per second squared times 80 meters that is 7 ,000 and 56 joules now let's answer questions here here we have to calculate change in energy in kinetic energy and that equals to the work of force f minus absolute work of the friction force, which is 9 ,600 joules minus 7 ,056 joules.
02:15
That is 2 ,500 and 44 joules...