A 72 kg bike racer climbs a 1200 -m-long section of road that has a slope of $4.3^{\circ} .$ By how much does his gravitational potential energy change during this climb?
Added by Luis B.
Step 1
We can use the formula for the height of a right triangle, which is h = L * sin(θ), where L is the length of the slope and θ is the angle of the slope. So, h = 1200 m * sin(4.3°) = 89.6 m. Show more…
Show all steps
Your feedback will help us improve your experience
Mahajan A and 65 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 76 kg bike racer climbs a 1300-m-long section of road that has a slope of 4.3°. Part A: By how much does his gravitational potential energy change during this climb?
Sufiyan A.
(1II) A bicyclist coasts down a $6.0^{\circ}$ hill at a steady speed of 4.0 $\mathrm{m} / \mathrm{s} .$ Assuming a total mass of 75 $\mathrm{kg}$ (bicycle plus rider), what must be the cyclist's power output to climb the same hill at the same speed?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD