00:01
Hello, here a block of metal has a mass of 100 kilograms and it's in question a dragged across a rough floor by using rope which is inclined at 30 degree to the horizontal.
00:16
The coefficient of static friction is 0 .75 and we have to determine the minimum force at which it can this block can be moved.
00:27
Let's make the sketch and here this minimum force.
00:40
Equals to times cosine alpha equals to the force of a static friction.
00:47
Normal reaction is here, here that is mg minus f, minimum sine alpha.
00:57
And as we know, force of static friction is coefficient of static friction times normal reaction.
01:03
Therefore, minimum force is coefficient of static friction mg, divided by cosine alpha plus coefficient of static equation, sine alpha.
01:31
Let's complete this calculation.
01:56
That's 592 newton.
01:59
So now that is solved.
02:02
Now let's move on to question b.
02:05
Now this block is being dragged across the slope, which is inclined that angle tether, which is 20 degree...