Question

a. A system uses 32-bit logical addresses, a 16K byte (2^14) page size, and 36-bit physical addresses (64 GB memory). What is the size of the page table?: ? 2^22 entries (2^36-14). ? 2^4 entries (2^36-32). ? 2^18 entries (2^32-14). ? 2^14 entries b. We had seen an example of determining the Working Sets using a given value of ?. For that example, obtain the value of WS(t1) and WS(t2) if ? = 5.

          a. A system uses 32-bit logical addresses, a 16K byte (2^14) page size, and 36-bit physical addresses (64 GB memory). What is the size of the page table?:

? 2^22 entries (2^36-14).
? 2^4 entries (2^36-32).
? 2^18 entries (2^32-14).
? 2^14 entries

b. We had seen an example of determining the Working Sets using a given value of ?. For that example, obtain the value of WS(t1) and WS(t2) if ? = 5.

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a. A system uses 32-bit logical addresses, a 16K byte (2^14) page size, and 36-bit physical addresses (64 GB memory). What is the size of the page table?:

? 2^22 entries (2^36-14).
? 2^4 entries (2^36-32).
? 2^18 entries (2^32-14).
? 2^14 entries

b. We had seen an example of determining the Working Sets using a given value of ?. For that example, obtain the value of WS(t1) and WS(t2) if ? = 5.

Added by Albert B.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Akash M

12/13/2023

Step 1

The size of the page table is determined by the number of pages that can be addressed by the logical address space. The number of pages is the size of the logical address space divided by the page size. In this case, the logical address space is 2^32 and the page Show more…

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a. A system uses 32-bit logical addresses, a 16K byte (2^14) page size, and 36-bit physical addresses (64 GB memory). What is the size of the page table? - 2^22 entries (2^36-14). - 2^4 entries (2^36-32) - 2^18 entries (2^32-14) - 2^14 entries b. We had seen an example of determining the Working Sets using a given value of Δ. For that example, obtain the value of WS(t1) and WS(t2) if Δ = 5.

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