Question

1. $x^2 - 4x + y^2 + z^2 = -\frac{15}{4}$ 2. $x^2 + y^2 + (z + 1)^2 = \frac{9}{4}$ 3. $x^2 - 4x + y^2 - 4y + z^2 - 2z = -\frac{35}{4}$ 4. $x^2 + y^2 + z^2 = 4$

          1. $x^2 - 4x + y^2 + z^2 = -\frac{15}{4}$
2. $x^2 + y^2 + (z + 1)^2 = \frac{9}{4}$
3. $x^2 - 4x + y^2 - 4y + z^2 - 2z = -\frac{35}{4}$
4. $x^2 + y^2 + z^2 = 4$

1. x^2 - 4x + y^2 + z^2 = -(15)/(4)
2. x^2 + y^2 + (z + 1)^2 = (9)/(4)
3. x^2 - 4x + y^2 - 4y + z^2 - 2z = -(35)/(4)
4. x^2 + y^2 + z^2 = 4

Added by Hayden N.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Patrick Vaughn

09/16/2020

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A B C D E F F 1. $x^2 - 4x + y^2 + z^2 = -\frac{15}{4}$ C 2. $x^2 + y^2 + (z + 1)^2 = \frac{9}{4}$ E A 3. $x^2 - 4x + y^2 - 4y + z^2 - 2z = -\frac{35}{4}$ 4. $x^2 + y^2 + z^2 = 4$