00:01
In this question the first case is when 100 volt with phase angle of 0 degree acting alone.
00:15
So, in this case the circuit is so this is a source here we have a resistance of 3 ohm and here we have inductance of x that is unknown to us.
00:36
So, the current flowing through this is i1 and the frequency is given as 120 hertz inductance of this is given as 2 .65 milli henry.
00:55
So, the reactance will be equal to j of omega l.
01:00
So, this can be written as j of 2 pi f l.
01:06
So, on solving this we will get j of 2 pi frequency is 120 and inductance is 2 .65 times 10 raised to the power minus 3 and this will be.
01:18
So, on solving this we will get 2 j is the inductance.
01:25
Now the current flowing i1 is equal to 100 volt at 0 degree phase divided by 3 plus 2 j.
01:36
So, on solving this we will get 23 .076 minus 15 .38 j and the phase angle will be of tan inverse of minus 15 .38 divided by 23 .076.
02:02
So, on solving this finally we will get current i1 is equal to 27 .735 and the phase angle will be negative of 33 .7 degree and this is in ampere.
02:16
So, this is i1 acting when 100 volt at 0 degree phase angle is allowed.
02:24
Now in the second case we have 80 volt at 0 degree phase acting.
02:33
So, again in this case we have frequency 60 hertz rest of the things are same as in the previous case.
02:41
So, again we will calculate xl that is j times 2 pi f l and so this will be j of 2 pi times 60 multiplied by 2 .65 multiplied by 10 raised to the power minus 3 ohm.
03:05
So, on solving this we will get xl equal to 1 j.
03:11
Now again this i2 will be equal to 80 volt at 0 degree phase divided by 3 plus j and this will be in ampere...