00:01
A ball is being tossed from a height of five meters above the ground, and it has an initial velocity of 8 meters per second.
00:09
So we know the ball is going to go to its maximum height where velocity is zero and come back down with the initial velocity of zero here.
00:19
Acceleration in this case is negative 9 .8 meters per second square because it is that due to gravity, and i'm taking the downward direction as negative.
00:27
So for the first thing we want to know is what is the maximum height above the ground this reaches? and so we're going to use the equation.
00:37
Final velocity squared is equal to initial velocity squared plus two times acceleration times displacement.
00:44
And in this case, it's going to be changed in why because it's going up and down.
00:48
So subtract initial velocity from both sides.
00:52
That's in subtract.
00:58
And divide both sides by two in acceleration.
01:00
So our equation is change in position is equal to final velocity squared minus initial velocity squared divided by two times acceleration, which is gravity.
01:14
And so our change in y is equal to zero minus eight squared divided by two times negative 9 .8.
01:24
And when you do this, you get 3 .27 meters.
01:29
But that's not including the five.
01:31
We want to know above the ground.
01:32
So we add five to that.
01:33
So our total distance is 3 .27 plus 5...