A ball thrown at an initial angle of 37.0∘ and initial velocity vi = 21.0 m/s reaches a maximum height h, as shown in With what initial speed must a ball be thrown straight up to reach the same maximum height hh?
Added by Allison W.
Step 1
First, let's find the time it takes for the ball thrown at an angle of 37.0∘ to reach its maximum height. We can use the equation for vertical motion: h = (vi^2 * sin^2θ) / (2g) where h is the maximum height, vi is the initial velocity, θ is the angle of Show more…
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