00:01
Okay, the maximum height happens when the y component is zero, the velocity, y component of the velocity is zero.
00:08
So this is 100 sine of 45, which is 50 root 2.
00:17
Okay, so then 50 root 2 minus 1 over 2, gt squared is the y component of the velocity, set it to zero.
00:29
And g is 32, so from here, 50 root 2 is equal to, no i'm sorry, that's not the right formula, not gt squared.
00:49
We're using the v final minus v initial is equal to gt, so 50 root 2 is the initial, or zero minus 5 initial is equal to negative gt.
01:08
Okay, so then 50 root 2 is equal to 32t, so from here, t comes out to be 2 .21 seconds, and then the maximum height is 3 plus y, vy component times time, 2 .21 minus 1 over 2 gt squared, which is 16t squared.
01:50
And let me calculate that.
01:58
Okay, the maximum height is 81 .12 feet.
02:08
Okay, maximum height.
02:12
Now, the ball is 300 feet from the plate, you know, so that means the x component of the velocity times time is going to be equal to 300.
02:30
So, in other words, what time is it going to reach to the end of the, or 300 feet, which is the end of the path...