A baseball pitcher throws a fastball horizontally at a speed of 42.0 $\mathrm{m} / \mathrm{s} .$ Ignoring air resistance, how far does the ball drop between the pitcher's mound and home plate, 60 $\mathrm{ft} 6$ in away?
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Step 1
Given: Distance = 60 ft 6 in 1 ft = 0.3048 m 1 in = 0.0254 m Converting 60 ft 6 in to meters: 60 ft = 60 * 0.3048 m = 18.288 m 6 in = 6 * 0.0254 m = 0.1524 m Total distance = 18.288 m + 0.1524 m = 18.4404 m Show more…
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