A baseball pitcher throws a fastball horizontally at a speed of 42.0 $\mathrm{m} / \mathrm{s} .$ Ignoring air resistance, how far does the ball drop between the pitcher's mound and home plate, 60 $\mathrm{ft} 6$ in away?
Added by John E.
Step 1
We know that 1 foot is equal to 0.3048 meters. So, we have: 60 ft 6 in = 60.5 ft = 60.5 * 0.3048 m = 18.44 m Now, we need to find the time it takes for the ball to travel this distance horizontally. We can use the formula: time = distance / speed time = 18.44 Show more…
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