Question

A bead with mass $1.8 \times 10^{-2} \mathrm{kg}$ is moving along a wire in the positive direction of an $x$ axis. Beginning at time $t=0,$ when the bead passes through $x=0$ with speed $12 \mathrm{m} / \mathrm{s},$ a constant force acts on the bead. Figure $7-24$ indicates the bead's position at these four times: $t_{0}=0, t_{1}=1.0 \mathrm{s}, t_{2}=2.0 \mathrm{s}$ and $t_{3}=3.0 \mathrm{s}$ . The bead momentarily stops at $t=3.0 \mathrm{s}$ . What is the kinetic energy of the bead at $t=10 \mathrm{s} ?$

          A bead with mass $1.8 \times 10^{-2} \mathrm{kg}$ is moving along a wire in
the positive direction of an $x$ axis. Beginning at time $t=0,$ when
the bead passes through $x=0$ with speed $12 \mathrm{m} / \mathrm{s},$ a constant force acts on the bead. Figure $7-24$ indicates the bead's position at
these four times: $t_{0}=0, t_{1}=1.0 \mathrm{s}, t_{2}=2.0 \mathrm{s}$ and $t_{3}=3.0 \mathrm{s}$ . The bead momentarily stops at $t=3.0 \mathrm{s}$ . What is the kinetic energy of
the bead at $t=10 \mathrm{s} ?$

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Added by James S.

Principles of Physics

David Halliday , Robert Resnick , Jearl… 10th Edition

Chapter 7

Instant Answer

Solved by Expert Ze-Han Lee

07/14/2019

Step 1

- Mass of the bead, \( m = 1.8 \times 10^{-2} \, \text{kg} \). - Initial speed at \( t = 0 \), \( v_0 = 12 \, \text{m/s} \). - The bead momentarily stops at \( t = 3.0 \, \text{s} \), which means its velocity is zero at this time. Show more…

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A bead with mass $1.8 \times 10^{-2} \mathrm{kg}$ is moving along a wire in the positive direction of an $x$ axis. Beginning at time $t=0,$ when the bead passes through $x=0$ with speed $12 \mathrm{m} / \mathrm{s},$ a constant force acts on the bead. Figure $7-24$ indicates the bead's position at these four times: $t_{0}=0, t_{1}=1.0 \mathrm{s}, t_{2}=2.0 \mathrm{s}$ and $t_{3}=3.0 \mathrm{s}$ . The bead momentarily stops at $t=3.0 \mathrm{s}$ . What is the kinetic energy of the bead at $t=10 \mathrm{s} ?$

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