A beam of parallel rays is incident on a transparent slab of refractive index √3 making an angle 30° with the surface of the slab. If the width of incident beam of light is 1.732 mm, the width of refracted beam will be ?
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- Refractive index of the slab, \( n = \sqrt{3} \). - Angle of incidence with the surface of the slab, \( \theta_i = 30^\circ \). - Width of the incident beam, \( w_i = 1.732 \, \text{mm} \). Show more…
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