A ray of light enters a rectangular glass slab of refractive index √3 at an angle of incidence 60°. It travels a distance of 5cm inside the slab and emerges out of the slab. The perpendicular distance between the incident and the emergent rays will be ?
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Step 1
Step 1: Calculate the angle of refraction using Snell's Law: Given: Angle of incidence = 60°, Refractive index = √3 Using Snell's Law: sin(i) / sin(r) = n sin(60°) / sin(r) = √3 sin(r) = sin(60°) / √3 sin(r) = √3 / 2 r = sin^(-1)(√3 / 2) r = 30° Show more…
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