A block is pushed across a horizontal surface by the force shown. If the coefficient of kinetic friction between the block and the surface is 0.3, F = 26 N, theta = 20°, and M = 3 kg, what is the magnitude of the acceleration of the block? A block is sliding down an inclined plane. The mass of the block is 6 kg, the angle of incline is 32°, and the coefficient of kinetic friction is 0.21. Calculate the magnitude of acceleration of the block.
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The horizontal component (F_x) is Fcosθ = 26cos209° = -22.1 N (negative because it's in the opposite direction of the positive x-axis). The vertical component (F_y) is Fsinθ = 26sin209° = -15.6 N (negative because it's in the opposite direction of the positive Show more…
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