À block of mass 2.0 kg slides on a rough surface. At + = 0, its speed is 2.0 m/s. It stops after covering a distance of 20 cm because of the friction exerted by the surface on it. Find the work done by friction.
Added by Amara H.
Step 1
Given: Mass (m) = 2.0 kg Initial velocity (v) = 2.0 m/s Kinetic energy (KE) = 1/2 * m * v^2 KE = 1/2 * 2.0 * (2.0)^2 KE = 1/2 * 2.0 * 4.0 KE = 4.0 J Show more…
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