A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be?
Added by Arch K.
Step 1
Step 1: Calculate the vertical component of the velocity: Vertical component of velocity (Vy) = 0 + 10 * 10 = 100 m/s Show more…
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