Question

A Boomerang has mass \( m \) surface area \( A \), radius of curvature of lower surface \( =r \) and it is moving with velocity \( v \) in air of density \( \rho \). The resistive force on it should be: A \( \frac{2 \rho v A}{r^{2}} \log \left(\frac{\rho m}{\pi A r}\right) \) C \[ 2 \rho v^{2} A \log \left(\frac{\rho A r}{\pi m}\right) \]

          A Boomerang has mass \( m \) surface area \( A \), radius of curvature of lower surface \( =r \) and it is moving with velocity \( v \) in air of density \( \rho \). The resistive force on it should be:
A \( \frac{2 \rho v A}{r^{2}} \log \left(\frac{\rho m}{\pi A r}\right) \)
C
\[
2 \rho v^{2} A \log \left(\frac{\rho A r}{\pi m}\right)
\]

A Boomerang has mass m surface area A, radius of curvature of lower surface =r and it is moving with velocity v in air of density ρ. The resistive force on it should be:
A (2 ρ v A)/(r^2)log((ρ m)/(π A r))
C

2 ρ v^2 A log((ρ A r)/(π m))

Added by John D.

Understanding Physics

Karen Cummings, Priscilla W. Laws,… 1st Edition

Chapter 7

Instant Answer

Solved by Expert Anand Jangid

Step 1

- Mass of the boomerang: \( m \) - Surface area: \( A \) - Radius of curvature of the lower surface: \( r \) - Velocity: \( v \) - Air density: \( \rho \) Show more…

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A Boomerang has mass \( m \) surface area \( A \), radius of curvature of lower surface \( =r \) and it is moving with velocity \( v \) in air of density \( \rho \). The resistive force on it should be: A \( \frac{2 \rho v A}{r^{2}} \log \left(\frac{\rho m}{\pi A r}\right) \) C \[ 2 \rho v^{2} A \log \left(\frac{\rho A r}{\pi m}\right) \]