A cable that weighs 1/2 kg/meter is lifting a load of 150 kg (mass = 150 kg) that is initially at the bottom of a 50-meter shaft. How much work is required to lift the load 1/2 of the way up the shaft? (weight = mass * 9.8)
Added by Audrey Y.
Step 1
The work done (W) is equal to the force (F) times the distance (d). The force is equal to the weight of the load, which is mass times gravity. So, F = 150 kg * 9.8 m/s^2 = 1470 N. The distance is half the shaft, so d = 50 m / 2 = 25 m. Therefore, the work done to Show more…
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