00:01
In the given question, we have been given a group frequency of the weights and the group data is the weights of the apple and the number of apple has been given.
00:10
So we have considered number of apple to be the frequency.
00:14
And similarly, we have made more three columns of this cumulative frequency midpoint and the midpoint times frequency.
00:20
Now, in this question, for computing this midpoint, what we will be doing, we will be taking the lower class limit plus the upper class limit and we will be dividing by two.
00:30
That means we are taking the average and this will come to 414 .5 for the first row.
00:38
So this midpoint will be 414 .5.
00:41
Now similarly for the second row, this is going to be 420 plus 429 upon 2 and this comes to 424 .5.
00:51
So similarly we will be doing for the rest of the rows.
00:55
The third one will be 434 .5.
01:01
Similarly 444 .5 454 .5, 464 .5 and for the last one this will be 474 .5.
01:12
Now this cumulative frequency is the summation of the frequency table that we have.
01:17
So the first one will be 14.
01:19
The second one is going to be 14 plus the frequency for the second row.
01:23
That is 14 plus 20 and this will be 34.
01:27
For the third one this will be 76 similarly we will be having 130 175 193 and 200 so we have this thing now the last column is the midpoint that is this x value times the frequency so this 414 .5 times 14 that is the frequency of the first weight group and this will comes to 5803 for the second row similarly it is going to be 8 490 18249 the third one will be 24003 204552 .5 8361 and double 3 so this is the midpoint 5 times the frequency.
02:35
Now what we will be doing, we will be doing the total.
02:39
So the total of this midpoint times frequency, this comes to 28680 and the summation of frequency will be 200.
02:53
So now the first part of the question, that is we have to find the mean.
03:00
Now we will be using the formula for mean, that is the summation of midpoint times the frequency, upon the summation of frequency.
03:18
Now the summation of midpoint times frequency we have already calculated and that has come to 28680 and the summation of frequency is of 200.
03:27
So putting those values in the formula that is 88680 upon total 200.
03:37
So this is going to get us 443 .4 .4.
03:41
So our mean is 443 .4.
03:46
Now the second part of the question asks us about the median.
03:53
Now for median what we will be doing from the cumulative frequency table we will be seeing the estimated mean group.
04:12
We will check the estimated mean group...