18 \, \text{m/s} \) (upwards)
Time taken, \( t = 2.13 \, \text{s} \)
Acceleration due to gravity, \( a = -9.81 \, \text{m/s}^2 \) (downwards)
Using the formula \( s = ut + \frac{1}{2}at^2 \), we can calculate the displacement:
\[ s = (8.18 \times 2.13) +
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