00:01
So for this object that's thrown upward at 8 meters per second, it wants us to find out how tall this cliff is by the time it reaches the bottom if it takes 2 .35 seconds.
00:11
So we list all of our knowns, including the fact that at the bottom of the cliff, this position is zero.
00:17
And we use the equation, position equals initial position plus initial velocity times time plus 1ā2xceleration times time squared.
00:25
So our quadratic equation here.
00:27
So when we plug in all of the numbers and look for the initial position, we find that.
00:31
That it's 8 .26 meters.
00:34
So that's how tall the clip is compared to the bottom of the cliff, which is at zero.
00:39
The next part of the problem asks us to solve for time.
00:42
And this is a little bit trickier because it's asking us for time if the rock were thrown straight down at 8 meters per second instead of up in the air.
00:52
That means we don't actually know what its final velocity is when it hits the ground, which is going to make our lives kind of difficult...