00:01
In this question, we will be solving this using the molarity equation, where molarity is equal to the moles of solute per liter of solution.
00:18
For letter a, we are asked to solve for the molarity.
00:23
So let us first solve for the mole of solute here, which is the n .a2 chromate.
00:31
Where mole is equal to mass divided by molar mass, substituting 13 grams divided by 161 .97 grams per mole.
00:42
This is equal to 0 .0803 mole of n .a2 -cr .04.
00:51
So solving for molarity is equal to 0803 mole divided by liter solution, but we are given the volume in ml.
01:06
Let's convert this to a liter.
01:08
We have one liter is 1 ,000 ml.
01:11
Therefore, molarity is equal to 099m and a2 -cr -o4...