A cannonball is fired at 30.0 m/s horizontally from a cliff that is 78.5 m high. What is the speed of the cannonball 1.00 s later, how long does it take the cannonball to reach the ground below, and how far horizontally does the cannonball land?
Added by Jerry H.
Step 1
00 second: Given initial velocity along x direction (v_x) = 30.0 m/s Acceleration along y direction (a_y) = -9.81 m/s^2 Using the equation v_y = v_y0 + a_y * t, where v_y0 is the initial velocity along y direction: v_y = 0 - 9.81 * 1.00 v_y = -9.81 m/s The speed Show more…
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