A cantilever of length 2.5 m carries a uniformly distributed load of 16.4 kN per metre length over the entire length. If the moment of intertia of the beam = 7.95 x107 mm4 and value of E = 2 x 105 N/mm2 , Estimate the deflection at the free end.
Added by Andrea W.
Step 1
The total load on the beam can be calculated by multiplying the load per unit length (16.4 kN/m) by the length of the beam (2.5 m). Total load = 16.4 kN/m * 2.5 m = 41 kN Show more…
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A horizontal cantilever of length 3a carries two loads w1 at a distance a from the fixed end and w2 at a distance a from the free end. Show that the expression for the deflection at the free end is given by the equation below. If the cantilever is a 25 cm x 15 cm I-beam with a second moment of area I = 8000 cm^4 and a = 0.5 m, determine the values of w1 and w2 to produce a deflection of 2 mm at the free end, given σmax = 100 x 10^6 N/m^2; E = 204 x 10^9 N/m^2. δ = 2a^3 [2w1 + 7w2] / 3EI [Ans. 37.5 kN, 45.2 kN]
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