A car travels 20.0 km due north and then 35.0 km in a direction 60.0^∘ west of north. By the use

Name: A car travels 20.0 km due north and then 35.0 km in a direction 60.0^∘ west of north. By the use of the parallelogram method of graphical addition, find the magnitude and direction of the car's resultant displacement [ Use a graph sheet for your result)
Uploaded: 2024-10-11T02:58:08-08:00
Duration: 4 min 41 s
Channel: Supratim Pal
Description: A car travels 20.0 km due north and then 35.0 km in a direction 60.0^∘ west of north. By the use of the parallelogram method of graphical addition, find the magnitude and direction of the car's resultant displacement [ Use a graph sheet for your result)

Step 1: Draw the first vector. This vector represents the car's initial 20.0 km journey due nort

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A car travels 20.0 km due north and then 35.0 km in a direction \( 60.0^{\circ} \) west of north. By the use of the parallelogram method of graphical addition, find the magnitude and direction of the car's resultant displacement [ Use a graph sheet for your result)

          A car travels 20.0 km due north and then 35.0 km in a direction \( 60.0^{\circ} \) west of north. By the use of the parallelogram method of graphical addition, find the magnitude and direction of the car's resultant displacement [ Use a graph sheet for your result)