A case of disputed paternity involves a woman, her children...

A case of disputed paternity involves a woman, her children (1, 2, and 3), and two men (Y and Z). The analysis is limited to the ABO and Rh blood group systems. Using the space below, and assuming that only Y or Z could be the biological father, assign each child to his/her possible father. You can use either Punnett squares for each trait, or the process of elimination. There may be more than one possible father for a particular child. The phenotypes are shown in the table. Mother: A, Rh- Possible Fathers: Y: B, Rh+ Z: AB, Rh- Children: 1: A, Rh+ 2: AB, Rh+ 3: O, Rh- Remember that in the ABO blood group system, A and B are codominant, and both are dominant over the recessive O allele. Rh has two alleles, D and d. Rh- is the recessive form, associated with the genotype dd.

Transcript

00:02 So in a case of the spirit of paternity involves a woman, her three children one, two three, and then two possible father, y and z.

00:10 So using a pundit square or the space below to assume that only y or z could be the biological father, assign each child to his or her possible father.

00:22 You can either use pudnettar square or process of elimination.

00:27 So first of all, let's talk about the abo blood type.

00:30 A and b are codominant, but they're both dominant to recessive allio, o, which i use lower i to represent.

00:40 Rh has two allele as well.

00:42 Kaptody stand for rh positive and lower d stand for rh negative.

00:48 And since it's recessive allio, rh negative has a genotype of homozygous lower d.

00:53 So let's start from child number three.

00:56 So child number three has type o and rh negative.

00:59 So we know that child 3's genotype must be homozygars lower i recessive and homozygars lower d recessive.

01:07 So let's take a look at the mother and the man z.

01:10 So mother has a type a and rh negative.

01:15 So her genotype must be homozygars ia or homozygars lower d.

01:21 That's the first possible genotype.

01:25 Another possible genome type will be heterozygars a with a lower i and the homozygars lower i for z, he has type ab and rh negative.

01:36 So z's genotype must be a, i, i, b, and homozygars lower d.

01:43 So let's take a look at abial blood type only.

01:48 Ignore the rh first.

01:50 So mother has two possible genotype, homozygars a or heterozygous a and i.

01:56 So let's take a look at the first case.

01:58 If the mother's genotype is homozygars a, and if z is the father, then he will give two alleles.

02:06 They're different, i, a, and i, b.

02:08 So i put z's alleles on a side, mothers on top...

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