00:02
Hello, we are given a relation on the set of rational numbers and the relation is defined by x is related to y if and only if x equal to y plus 6k for some k in integers.
00:18
Note that this condition is equivalent to the condition that x minus y is a integer multiple of 6 or 6 times k for some k belongs to integers.
00:26
Now the first question about this relation is e star reflexive.
00:30
The answer is yes.
00:32
Now x minus x is equal to 0 and 0 we can write as 0 times 6 and 0 belongs to integers.
00:39
So x star x so x is related to x for all x belongs to r.
00:46
Now second question is e star symmetric.
00:49
The answer is yes.
00:50
Suppose x is related to y.
00:52
This implies that x equal to y plus 6k for some k belongs to integers.
00:58
But this implies that y is equal to x minus 6k.
01:01
But this implies that y is equal to x plus 6 times minus k.
01:06
Now as k belongs to integers minus k will belong to integers.
01:10
So this will imply that y is equal to x plus integer multiple of 6.
01:16
So y is related to x.
01:17
Now x is related to y and y is related to x.
01:20
And this holds good for arbitrary pairs of elements in q.
01:26
So x star y is symmetric.
01:30
Now the next question is is the relation anti -symmetric.
01:36
The answer is no.
01:38
Note that 6 is related to 0 as 6 is equal to 0 plus 1 times 6.
01:44
And 0 is related to 6 as star is arbitrary.
01:49
Sorry star is symmetric.
01:52
But we can directly also we can again prove it also that 0 equal to 6 plus 6 times minus 1...