A certain vehicle depreciates according to the following formula. v(t)=66,000/(5+0.2t+0.3t2) where v(t) is the value of the vehicle in time t. Find the rate of change at which the value of this car is changing in 4 years. Round your answer in two decimal places.
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The value of the vehicle is given by the function \( v(t) = \frac{66,000}{5 + 0.2t + 0.3t^2} \). We need to find the rate of change of this value at \( t = 4 \) years, which means we need to compute the derivative \( v'(t) \). Show more…
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