00:01
Hi, in this question we have to find out the percentage ionization of acid, that is weak acid here.
00:06
Now, ha is a weak acid, so it will dissociate into ions in the solution as this.
00:11
So now, initially, we are given with concentration of this weak acid as 0 .10 molar, and these ions concentration will be 0.
00:21
So, after dissociation, that is, at equilibrium, when ions and this ha will be in equilibrium with each other, we have a concentration of h -positive ions will be 0 .10 into alpha molar.
00:36
For h -a negative also, 0 .10 into alpha -molar.
00:41
And concentration of h -a will be now 0 .10 into 1 -1 -1 -alpha molar.
00:47
Now here, alpha is the ionization constant.
00:56
Now, for this, ka is the dissociation constant.
01:00
So it will be equal to concentration of ions, that is products, that is h -positive ion concentration into a -negative ion concentration divided by the concentration of acid at equilibrium, h -a.
01:14
Now, k -a value is given, that is 1 .9 into 10 -raise -to -power minus 7, that is equal to 0 .10 alpha into 0 .10 alpha divided by h -a -k -a -8.
01:33
Concentration is 0 .10 1 minus alpha...