00:01
Hi, here in this given problem there is a uniform electric field in vertically upward direction and there is a charge queue placed in this electric field.
00:27
So as electric field always from positive to negative, so negativity will be upward, positivity will be downward and the charge is positive this charge is given as 29 .0 kulum or we can say this is 29 .0 into 10 raised to the power minus 9 kulam.
00:55
Electric field this is given as 5 .00 into 10 to the power 4 newton perculane.
01:05
Now in the first part of the problem it is given that the distance moved by the charge upward direction in upward direction as it will experience a force in upward direction.
01:19
So that distance moved by the charged particle in the upward direction.
01:40
Is s is equal to 0 .660 meter.
01:48
So work done by electric field will be given by the product of the force supplied by the electric field with the distance and multiplied by the angle, cosine of angle between the electrostatic force and the displacement and as both are in the same direction.
02:11
So this angle will come out to be 0.
02:14
And for the force we will use an expression for the electrostatic force q into e...