00:01
Hello, here we have to solve the following problem.
00:03
The charge of negative 3 and the half nanoculum is placed at origin.
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And the second charge of 2 .15 nanoculum is placed on y -axis at y2 of 4 .15 centimeters.
00:24
The third charge of 5 nanoculum is placed at x3 of 3 .3.
00:34
3.
00:35
16 centimeters and y3 of 4 .15 centimeters.
00:42
So, here we have to find x and y components of the total force exerted on discharge by two other charges.
00:50
So that will be our question a.
00:53
So here we have to find f3x and fy3y.
00:59
Let's sketch this system.
01:08
Q1 is negative.
01:11
Q2 is positive.
01:14
And q3 is also positive and here x3 is the same as x2 now let's sketch the forces f2 is directed to the left and f1 is directed towards charge 1 now let's scale let's show angle alpha which describes the direction of f1 and alpha equals to a tangent of y3 over x3.
02:26
That is 52 .8 degree.
02:38
So now to answer question a, we first will calculate force f1.
02:44
It's absolute value.
02:45
So the force f1 is k, q1, q3 over the distance, square distance, which is 63 squared, plus y3 squared...