00:02
So for this problem, we need to calculate the milliliters of each of the solution that must be used in this case.
00:12
So we're going to let ads to be the milliliters of the 34 % solution in here that is going to be the silver.
00:30
Nitrate, silver nitrate, and the order remaining is going to be the 100 minus x.
00:47
This is going to be the milliliters of the 4 % of silver nitrate and for the other 4 % of this.
01:03
So with that said, and this is give us a mixture that is 7 % silver nitrate.
01:13
So with that said, we know that in this case, the equation that results from this, from this information is that 0 .34, which is this percent in here, we can write that as 0 .34, plus the other percent of this, that is 0 .04 times the quantity of this, that is 100 minus ads.
01:40
This should be equal to the total content of this times the percentage, the final percentage that we are given, that is 0 .07, which is the same as 7%.
01:52
So now what we need to do is to simplify things in here.
01:58
So we will have that this is 0 .34 plus 4 minus 0 .6 .6 .7.
02:07
Then this is equal to 7.
02:13
So we just need to solve for x.
02:16
So once we solve for x, we will have that is equal to 0 .34 plus 4 minus 7 and this divided by 0 .04.
02:33
So let me see what we obtained from this...