A circular tube part of a heat exchanger is shown below. A hot fluid enters the tube at a temperature $T_{m,i} = 85^circ C$ and a mass flow rate of 10 kg/hr. We can assume that the flow is such that both boundary layers (thermal and velocity) can be considered fully developed. This hot fluid exits the tube at a temperature $T_{m,o} = 40^circ C$. The cooling fluid that circulates around the tube is at $T_{infty} = 25^circ C$. The tube diameter is 1 cm and 1 m long. We can neglect the tube thickness. $T_{infty} = 25^circ C$ $T_{m,o}$ $L = 1 ext{ m},$ $D = 1 ext{ cm}$ $dot{m}$ $T_{m,i} = 85^circ C$ Suddenly, the hot fluid mass flow rate is increased to 30 kg/hr. Find the new fluid exit temperature ($T_{m,o}$). Assume that the external flow is not affected in any way by the change of internal flow conditions. The hot fluid properties are given here : $ ho = 1079 ext{ kg/m}^3$, Cp=2637 J/kg.K, $mu$=0.0034 N.s/m$^2$ and k=0.261 W/m.K
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Q = 10*3600*2637*(85-40) = 5,174,220 J/hr Show more…
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A hot fluid passes through a thin-walled tube of 10 mm diameter and 1 m length, and a coolant at T∞ = 25°C is in cross flow over the tube. When the flow rate is m = 18 kg/h and the inlet temperature is Tm,i = 85°C, the outlet temperature is Tm,o = 78°C. Assuming fully developed flow and thermal conditions in the tube, determine the outlet temperature, Tm,o, if the flow rate is increased by a factor of 2. That is, m = 36 kg/h, with all other conditions the same. The thermophysical properties of the hot fluid are ρ = 1079 kg/m³, cp = 2637 J/kg · K, μ = 0.0034 N · s/m², and k = 0.261 W/m · K.
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