00:01
Hi, today we are solving the question in which firstly we need to determine the demands for x and y when p is given as $5 and q is given as $30.
00:16
So here x is equals to 611 -3q and y is equals to 928 plus p minus 4q.
00:32
So first of all taking x is equals to 611 -3 into 30 so we get 611 -90 on solving it we get it as 521.
00:58
Similarly if we put y value so 928 plus 5 minus 4 into 30 so we get y is equals to 933 minus 120 so it is equals to 813.
01:24
So we get x and y value now given that p is equals to 80 and q is equals to 90.
01:38
So if we substitute x is equals to 611 -3 into 90 so it will be 611 -270.
01:50
So we will get 341 and for y it is equals to 928 plus 80 minus 4 into 90 so we get 801008 minus 360 so it will be 648.
02:44
So therefore we get x and y will be equal to 341 and 648.
03:04
Now from here secondly we need to find the maximum weekly profit.
03:15
So given that c is equals to 90x plus 30y and r is equals to px plus qy.
03:29
So here if we take c from here will be equals to 90x plus 30y r will be equals to p as given from here 928.
03:49
So p will be p into x plus q into y.
03:57
So p value will be from above we can take it as 80 and 90...