A. Complete the following questions. B. Check your neighbor's work - comment on 2 other people's submission e.g. "All answers correct", "I think #3 should be xxxx" Consider a single gene with two alleles denoted "A" and "a". If the allele frequencies are: f(A) = p f(a) = q and p + q = 1 The expected genotype frequencies under Hardy Weinberg equilibrium are: f(AA) = p2 for the AA homozygotes, f(aa) = q2 for the aa homozygotes f(Aa) = 2pq for the heterozygotes. and p2 + 2pq + q2 = 1 Hardy Weinberg Practice Questions: 1. If the frequency of a recessive allele is 0.3, what is the frequency of the dominant allele? 2. If the frequency of the homozygous dominant genotype is 0.36, what is the frequency of the dominant allele? 3. If the frequency of the homozygous recessive genotype is 0.49, what is the frequency of the dominant allele? 4. In a certain population, the dominant phenotype of a certain trait occurs 87% of the time. What is the frequency of the dominant allele? 5. If the frequency of the homozygous dominant genotype is 0.49, what is the frequency of the homozygous recessive genotype? __________
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Calculate the genotype frequencies: f(AA) P2 for the AA homozygotes, f(aa) = q2 for the aa homozygotes, f(Aa) Zpq for the heterozygotes: p2 + 2pq+q2 = 1 Show more…
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For the problems below assume all genes have only two alleles and there is a simple dominant recessive relationship. 1. If 98 out of 200 individuals in a population express the recessive phenotype, what percent of the population would you predict would be heterozygotes? (a) I have given you information on the frequency of the homozygous recessive (or q2). So start by determining q2 and then solving for q. (b) Now that you have q, you can solve for p. Remember there are only two alleles in the population, so if you add the frequency of the two alleles, you have accounted for all possibilities and it must equal 1. So p + q = 1. (c) Now what is the formula for heterozygotes? Think back to the Hardy-Weinberg equation -- it is dealing with the genotypes of individuals in the population. (d) Now that you have figured out the % of heterozygotes, can you figure out the % of homozygous dominant? Does the % of homozygous dominant, heterozygotes and homozygous recessive individuals add up to 100%? If not, you have made an error. Those are the only three genotypes possible with only two alleles and a simple dominant and recessive relationship.
Maitreya E.
For the problems below, assume all genes have only two alleles and there is a simple dominant-recessive relationship. If 98 out of 200 individuals in a population express the recessive phenotype, what percent of the population would you predict would be heterozygotes? (a) I have given you information on the frequency of the homozygous recessive (or q2). So start by determining q2 and then solving for q. (b) Now that you have q, you can solve for p. Remember there are only two alleles in the population, so if you add the frequency of the two alleles, you have accounted for all possibilities and it must equal 1. So p + q = 1. (c) Now what is the formula for heterozygotes? Think back to the Hardy-Weinberg equation -- it is dealing with the genotypes of individuals in the population. (d) Now that you have figured out the % of heterozygotes, can you figure out the % of homozygous dominant? Does the % of homozygous dominant, heterozygotes and homozygous recessive individuals add up to 100%? If not, you have made an error. Those are the only three genotypes possible with only two alleles and a simple dominant and recessive relationship.
Kaela P.
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