A compound microscope has objective and eyepiece lenses of focal lengths 0.8 cm and 4.0 cm, respectively. If the microscope length is 15 cm and the eye near point is 25 cm, what is the magnification of the microscope?
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8 \, cm \). Substitute the values: \( \frac{1}{11} - \frac{1}{0.8} = \frac{1}{f} \) Solve for \( f \) to get \( f = 0.86 \, cm \). Show more…
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