Question

a) Consider the series connected AC circuit in Figure Q4(a). Calculate, i) the total impedance, $Z_{total}$ in the circuit ii) the supply current, $I_s$ iii) the real power, P in Watt and the reactive power, Q in Var $(173.21 + j100) V$ f = 60 Hz AC voltage $I_s$ $R = 10 \Omega$ Figure Q4(a) $L = 50 mH$ $C = 1 \mu F$

          a)
Consider the series connected AC circuit in Figure Q4(a). Calculate,
i) the total impedance, $Z_{total}$ in the circuit
ii) the supply current, $I_s$
iii) the real power, P in Watt and the reactive power, Q in Var
$(173.21 + j100) V$
f = 60 Hz
AC voltage
$I_s$
$R = 10 \Omega$
Figure Q4(a)
$L = 50 mH$
$C = 1 \mu F$

a)
Consider the series connected AC circuit in Figure Q4(a). Calculate,
i) the total impedance, Ztotal in the circuit
ii) the supply current, Is
iii) the real power, P in Watt and the reactive power, Q in Var
(173.21 + j100) V
f = 60 Hz
AC voltage
Is
R = 10 Ω
Figure Q4(a)
L = 50 mH
C = 1 μ F

Added by Mario C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sachin Rao

Step 1

In this case, we have a resistor (R) and an inductor (L) in series. The impedance of a resistor is given by the resistance itself, so the impedance of the resistor (Zr) is equal to R. The impedance of an inductor is given by the formula Zl = jωL, where j is the Show more…

Show all steps

Thanks for your feedback!

Consider the series connected AC circuit in Figure Q4(a). Calculate: i) The total impedance, Ztotal, in the circuit. ii) The supply current, I. iii) The real power, P, in watts and the reactive power, Q, in vars. Given: L = 50 mH R = 10 Î© (173.21 + j100) Î© f = 60 Hz AC voltage C = 1 F Figure Q4(a)