A consignment of 1,500 transistors were received by a company. A sample of 60 units are drawn randomly and tested the quality and found that 25 units were not meeting its quality then, estimate the variance in the total items.
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We need to estimate the variance in the total items based on the sample data provided. The sample size is 60, and 25 units out of these 60 do not meet the quality standards. Show more…
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From past experience, a company has found that in carton of transistors, 80% contain no defective transistors, 5% contain one defective transistor, 8% contain two defective transistors, and 7% contain three defective transistors. If the mean defectiveness is 0.42, find the variance and standard deviation Probablity Distribution: Don't round the values in table. Write all the values you get. x μ x-μ (x-μ)^2 P(x) (x-μ)^2.P(x) 0 0.42 1 0.42 2 0.42 3 0.42 Σ(x-μ)^2.P(x)= Varaince = ( 2 d.p.) Standard Deviation = ( 2 d.p.)
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From past experience, a company has found that in carton of transistors: 92% contain no defective transistors 3% contain one defective transistor, 3% contain two defective transistors, and 2% contain three defective transistors. Calculate the mean and variance for the defective transistors. Mean = Variance = (Please round answers to 4 decimal places.)
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