Question

A constant-volume calorimeter was calibrated by carrying out a reaction known to release 2.24 kJ of heat in 0.400 L of solution in the calorimeter (q=-2.24kJ), resulting in a temperature rise of 3.76 C. In a subsequent experiment, 200.0mL of 0.30 M HClO2 (aq) and 200.0 mL of 0.30 M NaOH (aq) were mixed in the same calorimeter and the temperature rose by 6.89 C. What is the change in the internal energy of the reaction mixture as a result of the neutralization reaction?

Name: a constant volume calorimeter was calibrated by carrying out a reaction known to release 224 kj of heat in 0400 l of solution in the calorimeter q 224kj resulting in a temperature rise of 37 66103
Uploaded: 2022-02-04T14:42:11-08:00
Duration: 2 min 11 s
Channel: David Collins
Description: a constant volume calorimeter was calibrated by carrying out a reaction known to release 224 kj of heat in 0400 l of solution in the calorimeter q 224kj resulting in a temperature rise of 37 66103

          A constant-volume calorimeter was calibrated by carrying out a reaction known to release 2.24 kJ of heat in 0.400 L of solution in the calorimeter (q=-2.24kJ), resulting in a temperature rise of 3.76 C. In a subsequent experiment, 200.0mL of 0.30 M HClO2 (aq) and 200.0 mL of 0.30 M NaOH (aq) were mixed in the same calorimeter and the temperature rose by 6.89 C. What is the change in the internal energy of the reaction mixture as a result of the neutralization reaction?

Added by David W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

02/04/2022

Step 1

The heat released during the calibration reaction is \( q = -2.24 \, \text{kJ} \) and the temperature rise is \( \Delta T = 3.76 \, \text{C} \). The heat capacity \( C \) of the calorimeter can be calculated using the formula: \[ C = \frac{q}{\Delta T} = Show more…

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A constant-volume calorimeter was calibrated by carrying out a reaction known to release 2.24 kJ of heat in 0.400 L of solution in the calorimeter (q=-2.24kJ), resulting in a temperature rise of 3.76 C. In a subsequent experiment, 200.0mL of 0.30 M HClO2 (aq) and 200.0 mL of 0.30 M NaOH (aq) were mixed in the same calorimeter and the temperature rose by 6.89 C. What is the change in the internal energy of the reaction mixture as a result of the neutralization reaction?