00:01
A couple has a child with type a blood.
00:05
If one parent is type o, what are the possible genotypes of the other parent? so we're talking about the a -b -o blood type.
00:13
There are three different alleles for the single gene.
00:16
I -a, i -b, and lower i.
00:21
A and b are dominant to lower i.
00:25
So what we know is that type a obviously will have two possible genotype, either homozygars, allele -a or heterozygars, a and low -i.
00:40
Same with type b, homozygars, b, allele, or b lower -i.
00:57
And then you have type a -b, a and b are co -dominant.
01:03
So this is going to be the genotype i -a and i -b at the same time.
01:10
The last one type o, there's only one type of possible genotype as well, homozygars lower i.
01:18
Only both alleles show recessive allel will give you a recessive phenotype.
01:24
So what we know is that this couple has a child with type a blood.
01:30
So that means the child has two possible genotype.
01:37
One is ia, ia, homozygars, or haterozygars.
01:49
Now, one of the parent is type o, but we can deduce that this parent must have a genotype of homozygous lower i.
02:05
This also tells us that the child must have a heterozygous genotype because the child will inherit ia, allio from one of the parents, and then the other lower eye must come from the other parents with type o.
02:23
So we know that parent one with type o blood contribute a lower eye allele to this child.
02:31
So the child must inherit the ia from another parent.
02:36
So this allele must from the other parent.
02:40
So parent number two will contribute ia...