A cylindrical vessel of uniform cross - section contains liquid up to the height H. At a depth h = H / 2 below the free surface of the liquid there is an orifice. Using Bernoulli's theorem, find the velocity of efflux of liquid.
Added by Nicholas H.
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At the free surface of the liquid, the pressure is atmospheric pressure (P0), the velocity of the liquid is almost zero (since it's not moving), and the height is H. Show moreā¦
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"A cylindrical vessel contains a liquid of density pup to a height h. The liquid is closed by a piston of mass m and area of cross-section A. There is a small hole at the bottom of the vessel. The speed v with which the liquid comes out of the hole is"
Jaya M.
If $A$ denotes the area of free surface of a liquid and $h$ the depth of an orifice of area of cross-section $a$, below the liquid surface, then the velocity $v$ of flow through the orifice is given by (a) $v=\sqrt{2 g h}$ (b) $v=\sqrt{2 g h} \sqrt{\left(\frac{A^{2}}{A^{2}-a^{2}}\right)}$ (c) $v=\sqrt{2 g h} \sqrt{\left(\frac{A}{A-a}\right)}$ (d) $v=\sqrt{2 g h} \sqrt{\left(\frac{A^{2}-a^{2}}{A^{2}}\right)}$
A cylindrical vessel contains a liquid of density $\rho$ upto a height $h$. The liquid is closed by a piston of mass $m$ and area of cross-section $A$. There is a small hole at the bottom of the vessel. The speed $v$ with which the liquid comes out of the hole is (a) $\sqrt{2 g h}$ (b) $\sqrt{2\left(g h+\frac{m g}{\rho A}\right)}$ (c) $\sqrt{2\left(g h+\frac{m g}{A}\right)}$ (d) $\sqrt{2 g h+\frac{m g}{A}}$
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