A DC self-excited shunt generator has a field resistance of 160Ω. The generated emf is 420V, and it supplies a load of 55,000W. Calculate the armature resistance when the generator terminal voltage is 408V.
Added by Heather E.
Step 1
We can use the formula P = IV, where P is power, I is current, and V is voltage. So, I = P/V = 55000W / 408V = 134.8A Show more…
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